The value of expression `(8^(0) - 3^(0) ) xx (8^(0) + 3^(0) )` is equal to

Options

A. 0
B. 1
C. 2
D. 3

Answer

To solve the expression \( (8^{0} - 3^{0}) \times (8^{0} + 3^{0}) \), we will follow these steps:

### Step 1: Evaluate \( 8^{0} \) and \( 3^{0} \)
According to the rules of exponents, any non-zero number raised to the power of 0 is equal to 1. Therefore:
\[ 8^{0} = 1 \quad \text{and} \quad 3^{0} = 1 \]

### Step 2: Substitute the values into the expression
Now we can substitute \( 8^{0} \) and \( 3^{0} \) into the original expression:
\[ (8^{0} - 3^{0}) \times (8^{0} + 3^{0}) = (1 - 1) \times (1 + 1) \]

### Step 3: Simplify the expression
Now simplify each part:
\[ 1 - 1 = 0 \quad \text{and} \quad 1 + 1 = 2 \]
So, the expression becomes:
\[ 0 \times 2 \]

### Step 4: Calculate the final result
Finally, we multiply:
\[ 0 \times 2 = 0 \]

Thus, the value of the expression \( (8^{0} - 3^{0}) \times (8^{0} + 3^{0}) \) is equal to **0**.

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