Home
Class 8
MATHS
Given that 4^(n-9) = 256, find the value...

Given that `4^(n-9) = 256`, find the value of `n`.

Text Solution

Verified by Experts

The correct Answer is:
13
Promotional Banner

Topper's Solved these Questions

  • EXPONENTS AND POWERS

    MTG IIT JEE FOUNDATION|Exercise Exercise (Subjective Problems) Long Answer Type|9 Videos

  • DIRECT AND INVERSE PROPORTIONS

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD/HOTS CORNER|15 Videos

  • FACTORISATION

    MTG IIT JEE FOUNDATION|Exercise OLYMPIAD/HOTS CORNER|10 Videos

Similar Questions

Explore conceptually related problems

If ^(n)P_(4)=360, find the value of n

If 9 xx 3^(n)=3^(6), find the value of n.

If 4^(x)=256, then find the value of 6^(2x-8)

Given X~B(n,p).If E(X)=6 and Var (X) = 4.2, find the value of n.

There are n arithmetic means between 9 and 27 . If the ratio of the last mean to the first mean is 2:1, find the value of n.

There are n AM's between 1&31 such that 7thmean: (n-1) thmean =5:9, then find the value of n .

If ""^(n)C_(8)= ""^(n)C_(9) , find the value of n.

If (n!)/(2!(n-2!)) and (n!)/(4!(n-4!)) are in the ratio 2:1, find the value of n.

There are nAM's between 1&31 such that 7 th mean :(n-1)th mean =5:9, then find the value of n

The nth term of a geometric progression is given by t_(n)=ar^(n-1) find the value of a, if t_(n)=32,r=4 and n=5 .