Total number of meiotic division required for forming 100 seeds of wheat is

Options

A. 100
B. 75
C. 125
D. 150

Answer

To determine the total number of meiotic divisions required for forming 100 seeds of wheat, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Process**: In flowering plants like wheat, seeds are formed from ovules, which develop from megasporangia. Each ovule contains a megasporocyte (megaspore mother cell) that undergoes meiosis to produce megaspores.

2. **Meiotic Division**: Each megasporocyte undergoes one meiotic division to produce four megaspores. However, typically, only one of these megaspores survives and develops into the functional megaspore, while the other three degenerate.

3. **Calculating Functional Megaspores**: To produce 100 seeds, we need 100 functional megaspores. Since each meiotic division produces one functional megaspore, we need 100 meiotic divisions to produce 100 functional megaspores.

4. **Total Meiotic Divisions**: Since each meiotic division results in the formation of four megaspores, we can calculate the total number of meiotic divisions required. For every functional megaspore, we need one meiotic division. Therefore, for 100 functional megaspores, we need 100 meiotic divisions.

5. **Final Calculation**: The total number of meiotic divisions required for forming 100 seeds of wheat is 100.

### Final Answer:
The total number of meiotic divisions required for forming 100 seeds of wheat is **100**.

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