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If mother and father are both sickle cel...

If mother and father are both sickle cell carriers, what are the chances that the child will not have the trait?

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To determine the chances that a child will not have the sickle cell trait when both parents are carriers, we can follow these steps: ### Step 1: Understand the Genetics of Sickle Cell Anemia Sickle cell anemia is caused by a mutation in the hemoglobin gene and is inherited in an autosomal recessive manner. This means that a child must inherit two copies of the mutated gene (one from each parent) to express the disease. ### Step 2: Identify the Genotypes of the Parents Both parents are carriers of the sickle cell trait. Their genotypes can be represented as: - Mother: HBA HBS (carrier) - Father: HBA HBS (carrier) ### Step 3: Set Up a Punnett Square To find the possible genotypes of the offspring, we can use a Punnett square. The alleles from each parent are placed on the top and side of the square: | | HBA | HBS | |-------|------|------| | **HBA** | HBA HBA | HBA HBS | | **HBS** | HBA HBS | HBS HBS | ### Step 4: Determine the Possible Offspring Genotypes From the Punnett square, we can see the possible genotypes for the children: 1. HBA HBA (normal, not a carrier) 2. HBA HBS (carrier) 3. HBA HBS (carrier) 4. HBS HBS (affected by sickle cell anemia) ### Step 5: Count the Outcomes Now, let's count the outcomes: - 1 child with genotype HBA HBA (normal) - 2 children with genotype HBA HBS (carriers) - 1 child with genotype HBS HBS (affected) ### Step 6: Calculate the Probability To find the probability that a child will not have the sickle cell trait, we consider the outcomes that do not express the trait: - HBA HBA (normal): 1 outcome - HBA HBS (carrier): 2 outcomes Total outcomes = 4 (1 normal + 2 carriers + 1 affected) The probability that a child will not have the sickle cell trait is: \[ \text{Probability} = \frac{\text{Number of non-affected outcomes}}{\text{Total outcomes}} = \frac{3}{4} = 75\% \] ### Conclusion The chances that the child will not have the sickle cell trait are 75%. ---
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CENGAGE BIOLOGY-CHROMOSOMAL THEORY OF INHERITANCE AND GENETIC DISORDERS-MANDATORY EXERCISE
  1. Mention the salient features of chromosomal theory of inheritance.

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  2. Sex of the offspring is determined by (A) only the mother, because s...

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  3. Down's syndrome is an example of (A) incomplete dominance (B) gene...

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  4. What are the main conventional symbols and signs used in genetic famil...

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  5. The genetic disorders can be grouped under two broad categories - sex-...

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  6. The egg of an animal contains 10 chromosomes, of which one is X chromo...

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  7. How is the child affected if it has grown from the zygote formed by an...

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  8. A woman of 47 years delivered an abnormal child with flattened nasal b...

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  9. In humans the sex of the child is determined by the father and not by ...

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  10. Pattern baldness is sex-linked, but cannot be expressed normally in fe...

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  11. Action of ultraviolet rays on DNA is (A) induction of thymidine dime...

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  12. A women with normal vision, but whose father was colour blind, marries...

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  13. Haemophilia is a condition, where there is (A) no production of haem...

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  14. A woman who has haemophilia marries a normal man. How many of their ch...

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  15. Identify each of the alterations of chromosome structure.

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  16. How does sickle cell anemia affect the red blood cells?

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  17. If mother and father are both sickle cell carriers, what are the chanc...

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