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For a reaction between gaseous compounds...

For a reaction between gaseous compounds.`2A+BtoC+D`. The reaction rate = K[A][B]. If the volume of the container is made 1/4 of the initial, then what will be the rate of reaction as compared to the initial rate?

A

16 times

B

4 times

C

1/8 times

D

1/16 times

Text Solution

Verified by Experts

The correct Answer is:
A
If volume becomes 1/4 of initial volume then concentration becomes 4 times.
`("Final rate")/("Initial rate")=(K[4A][4B])/(K[A][B])=16:1`
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