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""^(23)Na is more stable isotope of Na. ...

`""^(23)Na` is more stable isotope of Na. Find out the process by which `""_(11)^(24)Na` can undergo radioactivity decay.

A

`beta`-emission

B

`alpha`-emission

C

`gamma`-emission

D

k-electron capture

Text Solution

Verified by Experts

The correct Answer is:
A
`(n)/(p)gt1` higher than stable nuclei so `beta`-emission
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CENGAGE CHEMISTRY-RADIOACTIVITY-MANDATORY EXERCISE (SET I)
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