The amount of C-14 isotope in a piece of wood is found to be 1/16th of its amount present in a fresh piece of wood. Calculate the age of wood. Half life period of C-14 is 5760 years.

Explanation

Let the amont of `""^(14)C` in fresh wood number be a.
Therefore, amount of `""^(14)C` is the piece of wood after disintegration `(N)=(a)/(16)`
`t_(1//2)=5760` years
`t=?`
`lambda=?`
`lambda=(0.693)/(t_(1//2))=(0.693)/(5760)=1.203xx10^(-4)y^(-1)`
`t=(2.303)/(lambda)log""(N_0)/(N)`
`t=(2.303)/(1.203xx10^(-4))log""(a16)/(a)`
`=23051.44` years