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Solve the equation: (x-a)/(x-b)+(x-b)/(x...

Solve the equation: `(x-a)/(x-b)+(x-b)/(x-a)=(a)/(b)+(b)/(a)`

Text Solution

Verified by Experts

The correct Answer is:
`x=0` or `(a+b)`
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Solve the following quadratic equations by factorization: (x-a)/(x-b)+(x-b)/(x-a)=(a)/(b)+(b)/(a)

both roots of the equation (x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0 are

Knowledge Check

  • Solve the equation : (a)/(x-b)+(b)/(x-a)=2" "(xneb,a)

    A
    `x = a-b and x= (a-b) / (2)`
    B
    `x = a-b and x= (a+b) / (2)`
    C
    `x = a+b and x= (a-b) / (2)`
    D
    `x = a+b and x= (a+b) / (2)`

  • If the roots of the equation (x-b) (x-c) + (x-c) (x-a) + (x-a) (x-b)=0 are equal, then

    A
    a+b+c =0
    B
    `a+b omega +c omega^(2)=0`
    C
    `a-b+c=0`
    D
    `a+b omega^(2)+c omega =0`

  • Both the roots of the equation (x-a) (x-b) +(x-b) (x-c) +(x-c) (x-a)=0 are always

    A
    positive
    B
    negative
    C
    real
    D
    none of these

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    The roots of the equation of the given equation (x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0 are always

    The roots of the equation of the given equation (x-a)(x-b)+(x-b)(x-c)+(x-c)(x-a)=0 are always

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