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What is the value of gravitational const...

What is the value of gravitational constant `G=6.67xx10^(-11)Nm^(2)//kg^(2)` in CGS units?

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To convert the gravitational constant \( G = 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \) from SI units to CGS units, we will follow these steps: ### Step 1: Write down the given value of \( G \) We start with the gravitational constant in SI units: \[ G = 6.67 \times 10^{-11} \, \text{Nm}^2/\text{kg}^2 \] ...
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Calculate the force of attraction between two balls each of mass 10kg when their centres are 10 cm apart. The value of gravitational constant G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)

The mass of a planet is 6xx10^(24) kg and its diameters is 12.8 xx 10^(3) km. If the value of gravitational constant be 6.7xx10^(-11) NM^(2)//Kg^(2) ,Calculate the value of acceleration due to gravity on the surface of the planet.What planet could this be ?

Knowledge Check

  • The value of universal gravitational constant G=6.67xx10^(-11)Nm^(2)kg^(-2) . The value of G in units of g^(-1)cm^(3)s^(-2) is

    A
    `6.67xx10^(-8)`
    B
    `6.67xx10^(-7)`
    C
    `6.67xx10^(-9)`
    D
    `6.67xx10^(-10)`

  • The value of universal gravitational constant G = 6.67 xx 10^(-11) N m^(2) kg^(-2) . The value of G in units of g^(-1) cm (^(3)s^(-2) is

    A
    `6.67 xx 10^(-8)`
    B
    `6.67 xx 10^(-7)`
    C
    `6.67 xx 10^(-9)`
    D
    `6.67 xx 10^(10)`

    • Similar Questions

    Explore conceptually related problems

    If the value of universal gravitational constant is 6.67xx10^(11) Nm^2 kg^(-2), then find its value in CGS system.

    The value of gravitation is G = 6.67 xx 10^(-11)N-m^(2)/kg^(2) in SL units . Convert it into CGS system of units .

    Calculate the mass and density of the earth. Given that Gravitational constant G = 6.67 xx 10^(-11) Nm^(2)// kg^(2) , the radius of the earth = 6.37 xx 10^(6) m and g = 9.8 m//s^(2) .

    Find the gravitational force between the sun and the Jupiter. Given that the mass of the sun = 2 xx 10^(30) kg, the mass of the Jupiter = 1.89 xx 10^(27) kg, the radius of the Jupiter's orbit = 7.73 xx 10^(11) m and the value of universal gravitational constant G = 6.67 xx 10^(11) N m^(2) kg^ (2) .

    Determine the binding energy of satellite of mass 1000 kg revolving in a circular orbit around the Earth when it is close to the surface of Earth. Hence find kinetic energy and potential energy of the satellite. [Mass of Earth =6xx10^(24)kg , radius of Earth =6400km , gravitational constant G=6.67xx10^(-11)Nm^(2)//kg^(2) ]

    Mahendra nad Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them ? G=6.67xx10^(-11)N.m^(2)//kg^(2) .

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