1 mg =

A

`10^(-6)kg`

B

`10^(-4)kg`

C

`10^(3)kg`

D

`10^(-2)kg`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENT

    CENGAGE PHYSICS|Exercise MANDATORY EXERCISE (EXERCISE SET II) COMPREHENSION|1 Videos
  • UNITS AND MEASUREMENT

    CENGAGE PHYSICS|Exercise MANDATORY EXERCISE (EXERCISE SET II) MATCH THE COLUMNS|5 Videos
  • UNITS AND MEASUREMENT

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES |8 Videos
  • STATICS

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|9 Videos

Similar Questions

Explore conceptually related problems

v = 5 m s^(-1) W = mg = 100 N m = 10 kg Kinetic energy ??

Mass conversion: A sample fo platinum has a mass of 0.432 mg . What is its mass in kilogram? Strategy: Consturct the required unit factors using the relationship 1g = 1000 mg and 1 kg = 1000 g and follow the sequence mg rarr g rarr kg

A stone of mass m tied to one end of a string is revolved in a vertical circle of radius R the net forces at the lowest (F_(L) and highest (F_(H)) points of the circle directed vertically downwards are : (a) F_(L) = mg - T_(1) F_(H) = mg + T_(2) (b) F_(L) = mg + T_(1) , F_(H) = mg - T_(2) (c) F_(L) = mg + T_(1) - (m upsilon_1^(2))/(R) , F_(H) = mg - T_(2) + (m upsilon_(1)^(2))/(R ) (d) F_(L) = mg - T_(1) - (m upsilon_(1)^(2))/(R) , F_(H) = mg + T_(2) + (m upsilon_(2)^(1))/(R) Choose corret alternative T_(1), upsilon_(1) denote the tension and speed at the lowest point T_(2), upsilon_(2) denote corresponding valuse at the highest point .

Particle having a mass of 1.0 mg has a velocity of 3600 km/h. Calculate the wavelength of the particle.

The total number of electrons presnt in 1 mL Mg Given density of ._(12) Mg^(24) = 1. 2 g//mL .