A hot iron ball of mass 0.2 kg is dropped into 2 kg of water at `20^(@)C` . The final temperature of water becomes `25^(@)C` Calculate the initial temperature of iron.
`C_("iron")480 J kg^(-1) K^(-1), C_("water")=4200 J kg^(-1)K^(-1)`

Explanation

To find the initial temperature of the hot iron ball, we can use the principle of conservation of energy, which states that the heat lost by the iron ball will be equal to the heat gained by the water.

### Step-by-Step Solution:

1. **Identify the variables:**
- Mass of iron (m_iron) = 0.2 kg
- Specific heat of iron (C_iron) = 480 J/(kg·K)
- Mass of water (m_water) = 2 kg
...