Home
Class 10
PHYSICS
Find the heat needed to convert 10 g of ...

Find the heat needed to convert 10 g of ice at `0^(@)C` to water at `20^(@)C` .
Given `L_((ice))=336xx10^(3) J kg^(-1), C_(("water"))=4200 J kg K^(-1)`

Text Solution

AI Generated Solution

To find the heat needed to convert 10 g of ice at 0°C to water at 20°C, we need to consider two steps: 1. **Melting the ice into water at 0°C**. 2. **Heating the resulting water from 0°C to 20°C**. ### Step-by-Step Solution: **Step 1: Convert mass from grams to kilograms.** ...
Promotional Banner

Topper's Solved these Questions

  • HEAT AND TEMPERATURE

    CENGAGE PHYSICS|Exercise MANDATORY EXERCISE (Exercise Set I)|33 Videos

  • HEAT AND TEMPERATURE

    CENGAGE PHYSICS|Exercise MANDATORY EXERCISE (Exercise Set II)|36 Videos

  • HEAT AND MECHANICAL ENERGY

    CENGAGE PHYSICS|Exercise Olympiad and NTSE Level Exercises|7 Videos

  • LASERS

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES |1 Videos

Similar Questions

Explore conceptually related problems

Find the quantity of heat required to convert 40 g of ice at -20^(@) C into water at 20^(@) C. Given L_(ice) = 0.336 xx 10^(6) J/kg. Specific heat of ice = 2100 J/kg-K Specific heat of water = 4200 J/kg-K

Find the result of mixing 1kg of ice at 0^(@)C with 1.5kg of water at 45^(@)C . (Specific latent heat of fusioin of ice =336xx10^(3)Jkg^(-1) )

Find the heat energy required to convert 10 g ice at 0^(@)C to steam at 100^(@)C . Specific latent heat of melting and vapourization are 336 KJ kg^(-1) and 2260 KJ kg^(-1) , respectively, and specific heat of water is 4200 J kg^(-1)K^(-1).

In an energy recycling process, X g of steam at 100^(@)C becomes water at 100^(@)C which converts Y g of ice at 0^(@)C into water at 100^(@)C . The ratio of X/Y will be (specific heat of water ="4200" J kg"^(-1)K, specific latent heat of fusion =3.36xx10^(5)"J kg"^(-2) , specific latent heat of vaporization =22.68xx10^(6)" J kg"^(-1) )

The power of a system which can convert 10 kg of water at 30^@ C into ice 0^@ C in one minute (L_(ice) = 336000 J//Kg and S_(water) = 4200 J//kg//K ) will be

Calculate the amount of head required to convert 1.00kg of ice at - 10^(@)C into stream at 100^(@)C at normal pressure Specific heat of ice = 2100J kg^(-1)K^(-1) intent heat of fusion of ice = 3.36 xx 10^(5)Jkg^(-1) specific heat capacity of water = 4200 Jkg^(-1)k^(-1) and latent head of vaporisation of water = 2.25 xx 10^(6)J kg^(-1)