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A copper wire of length 1 m is heated fr...

A copper wire of length 1 m is heated from `20^(@)C` to `120^(@)C`. If the length increases by 1.7 mm, calculate it’s `alpha`

Text Solution

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`alpha=(DeltaL//L_(1))/(DeltaT)=((L_(2)-L_(1))/(L_(1))/(DeltaT)=((1.7xx10^(-3))//1)/(100)=17xx10^(-6)//^(@)C`
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