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A ball of diameter 5.01 cm is placed on ...

A ball of diameter 5.01 cm is placed on an iron ring of diameter 5 cm. What should be the increase in temperature of the ring so that the ball just passes through the ring?
`a_(("iron"))=12xx10^(-6)//""^(@)C`

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AI Generated Solution

To find the increase in temperature of the iron ring so that the ball just passes through it, we can follow these steps: ### Step 1: Determine the change in diameter The diameter of the ball is 5.01 cm, and the diameter of the ring is 5 cm. The change in diameter required for the ball to pass through the ring is: \[ \Delta D = D_{\text{ball}} - D_{\text{ring}} = 5.01 \, \text{cm} - 5 \, \text{cm} = 0.01 \, \text{cm} \] ...
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