A 15 g ice cube at `0^(@)C` is dropped into 100 g of water at `30^(@)C` . Calculate the final temperature of water after the full ice has melted, given `L_(ice)=336xx10^(3)J kg^(-1), C_("water")=4200 J kg^(-1)K^(-1)`

Explanation

Let the final temperature be T.
Heat required to melt ice =mL
`=15x10^(-3)xx336xx10^(3)`
`Q_(1)=5040J`
Heat required to rise the molten ice to `T^(@)C=`
`(mxxC xx DeltaT)_("water")=15xx10^(-3)xx4200xxT`
`Q_(2)=63J`
Heat lost by water `=(mxxC xx DeltaT)_("water")`
`=100xx10^(-3)xx4200xx(30-T)`
`Q_(3)=420(30-T)`
If there no losses, `Q_(1)+Q_(2)=Q_(3)`
`:. T=17.9^(@)C`