Two equal charges repel each other with a force of `4 xx 10^(-5)`N. when they are 0.03 m apart in air. Find the magnitude of the charges. What will be the force if the distance between them is doubled?

Explanation

To solve the problem, we will use Coulomb's Law, which states that the force (F) between two point charges (q1 and q2) is directly proportional to the product of the magnitudes of the charges and inversely proportional to the square of the distance (r) between them. The formula is given by:

\[ F = k \frac{q_1 \cdot q_2}{r^2} \]

Where:
- \( F \) is the force between the charges,
- \( k \) is Coulomb's constant, approximately \( 8.99 \times 10^9 \, \text{N m}^2/\text{C}^2 \),
- \( q_1 \) and \( q_2 \) are the magnitudes of the charges,
...