Home
Class 10
PHYSICS
A 2 V cell is connected to a 1 ohm resis...

A 2 V cell is connected to a 1 `ohm` resistance. How many electrons come out of the negative terminal of the cell in 2 minutes?

Text Solution

Verified by Experts

Current through the resistance
`I=V/R=2 ` amperes
Number of electrons coming out in
1 second `=2/("electronic charge")=2/(1.6xx10^(19)`
`=1.25xx10^(+19)`
Number of electrons coming out in 2 minutes or 120 s
`=1.25xx10^(19)xx120`
`=1.5xx10^(21)` electrons
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|10 Videos

  • CURRENT ELECTRICITY

    CENGAGE PHYSICS|Exercise MANDATORY EXERCISE(EXERCISE SET VI)|5 Videos

  • ATOMIC AND NUCLEAR PHYSICS

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES |8 Videos

  • ELECTROMAGNETIC INDUCTION

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|10 Videos

Similar Questions

Explore conceptually related problems

A 2-V cell is connected to a 1-Omega resistor . How many electrons come out of the negative terminal of the cell in 2 minutes ?

A cell of emf 'E' is connected across a resistance R.The potential difference between the terminals of the cell is found to be "V" .The internal resistance of the cell must be:

Knowledge Check

  • A cell has emf of 2.2 V, when connected to a resistance of 5 Omega , the potential difference between the terminals of the cell becomes 2.1 V, the internal resistance for the cell is

    A
    `0.12 Omega`
    B
    `0.48 Omega`
    C
    `0.24 Omega`
    D
    `0.50 Omega`

  • The electrode connected to the negative terminal of the cell/battery is called the ___________

    A
    Anode
    B
    Cathode
    C
    Both (a) and (b)
    D
    None of these

  • A cell of e.m. E and internal resistance r is connected across a resistancer. The potential difference between the terminals of the cell must be

    A
    E
    B
    `E//2`
    C
    `E//4`
    D
    `3//2`

    • Similar Questions

    Explore conceptually related problems

    A cell of emf E is connected across a resistance r . The potential difference between the terminals of the cell is found to be V . The internal resistance of the cell must be

    The reading on a high resistance voltmeter, when a cell is connected across it, is 2.2 V. When a 5 Omega resistance is connected across the terminals of the cell in parallel with the voltmeter, the reading is 1.8 V. Determine the internal resistance of the cell.

    Ansh made an electric circuit by using a dry cell , two electric wires and one electric bulb . First , he connected one end of wire to the positive terminal and another end of wire to the negative terminal of the cell .Now , he connect the bulb to the wire which is connected with the negative terminal of the cell .Does bulb glow ?

    N cells, each of emfE and internal resistancer, are connected in a closed ring so that the positive terminal of each cell is joined to the negative terminal of the next cell as shown in the adjoining diagram. Any two points of this ring are connected through an external resistance R. Find the current in R.

    Two cells X and Y are connected to a resistance of 10Omega shown in the figure. The terminal voltage of cell Y is:-

    Home
    Profile