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Two resistors of resistance 10Omega and ...

Two resistors of resistance `10Omega` and `20Omega` are connected in parallel. A battery supplies 6 A of current to the combination. Calculate the current in each resistor.

Text Solution

Verified by Experts

The current in the `10Omega` resistance is
`i_(1)=(R_(2))/(R_(1)+R_(2))i=((20)xx(6))/(20+10)=4A`
Thecurrent in the `20Omega` resistor is `i_(2)=(R_(1))/(R_(1)+R_(2))i=(10xx6)/(10+20)=2A`
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