Home
Class 10
PHYSICS
A cell supplies a current of 0.9 A throu...

A cell supplies a current of `0.9` A through a `2Omega` resistor and current of `0.3` A through a `7Omega` resistor What is the internal resistance of the cell ?

Text Solution

Verified by Experts

If E is the emf of the cell and r is its internal resistance, then
`(E)/(2+r)=0.9` . . . (1)
`(E)/(7+r)=0.3` . . . (2)
Dividing the two equations, we get
`(7+r)/(2+r)=(0.9)/(0.3)`
`:.r=0.5Omega`
Promotional Banner

Topper's Solved these Questions

  • SOURCES OF ELECTRIC CURRENT

    CENGAGE PHYSICS|Exercise CHALLENGING EXERCISE |10 Videos

  • SOURCES OF ELECTRIC CURRENT

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|10 Videos

  • SOURCES OF ELECTRIC CURRENT

    CENGAGE PHYSICS|Exercise MANDATORY EXERCISE (Exercise Set III)|1 Videos

  • REFRACTION OF LIGHT

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NSE LEVEL EXCERCISES |10 Videos

  • STATIC ELECTRICITY

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|10 Videos

Similar Questions

Explore conceptually related problems

A battery supplies a current of 0.9 A through a 2 Omega resistor and a current of 0.3 A through a 7 Omega resistor. Calculate the emf and internal resistance of the battery.

Current through the 5Omega resistor is

Current flowing through 4 Omega resistor is :

By a cell a current of 0.9 A flows through 2 ohm resistor and 0.3 A through 7 ohm resistor. The internal resistance of the cell is

The value of current through 2 Omega resistor is

Find the current through 12 Omega resistor in

Two identical cells connected in series send 1.0A current through a 5 Omega resistor. When they are connected in parallel, they send 0.8 A current through the same resistor. What is the internal resistance of the cell?

Electric current through 400 Omega resistor is :

In the arrangement the current through 5 Omega resistor is