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A wire of resistance 4Omega is connected...

A wire of resistance `4Omega` is connected to a battery having an internal resistance of `1Omega` For a current of 6 A to flow through the circuit what should be the emf of the battery ?

Text Solution

Verified by Experts

`I=(E)/(R+r)`
`E=I(R+r)`
`=6A(4Omega+1Omega)`
`=6Axx5Omega`
`E=30V`
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