Home
Class 10
PHYSICS
In the network shown the potential diffe...

In the network shown the potential difference between A and B is `(R=r_(1)=r_(2)=r_(3)=1Omega,E_(1)=3V,E_(2)=2V,E_(3)=1V)`

A

1 V

B

2 V

C

3 V

D

4 V

Text Solution

Verified by Experts

The correct Answer is:
B
No current through R, so potential difference
across AB is `V=((E_(1))/(r_(1))+(E_(2))/(r_(2))+(E_(3))/(r_(3)))/((1)/(r_(1))+(1)/(r_(2))+(1)/(r_(3)))=(3/1+2/1+1/1)/(1/1+1/1+1/1)=2V`
Promotional Banner

Topper's Solved these Questions

  • SOURCES OF ELECTRIC CURRENT

    CENGAGE PHYSICS|Exercise CHALLENGING EXERCISE |10 Videos

  • REFRACTION OF LIGHT

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NSE LEVEL EXCERCISES |10 Videos

  • STATIC ELECTRICITY

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|10 Videos

Similar Questions

Explore conceptually related problems

In the network shown the potential difference between A and B is (R = r_(1) = r_(2) = r_(3) = 1 Omega, E_(1) = 3V, E_(2) = 2V, E_(3) = 1V )

In Fig. key K is closed at t = 0 . After a long time, the potential difference between A and B is zero, the value of R will be [r_(1) = r_(2) = 1 Omega, E_(1) = 3 V and E_(2) = 7 V , C = 2 mu F , L = 4 mH , where r_(1) and r_(2) are the internal resistances of cells E_(1) and E_(2) , respectively].

Calculate the current through each resistance in the given circuit. Also calculate the potential difference between the points a and b. E_1 = 6V, E_2 = 8V, E_3 =10V , R_1 =5 Omega , R_2 =10 Omega, R_3 =4Omega Assume that all the cless have no internal resistance.

Four resistors R_(1),R_(2),R_(3) and R_(4) are connected between two terminals A and B iin a network as shown in the diagram. A key K can connect the two points (see diagram) C and D. A constant potential difference (V_(A)-V_(B))=V is maintained between thhe points A and B Q. If R_(1)=R_(4)=1Omega and R_(2)=R_(3)=2Omega , the effective resistance between the terminals A and B will change, on closing the key K, by

Three voltmeters A, B and C having resistances R, 1.5 R and 3 R respectively are used in a circuit as shown. When a potential difference is applied between X and Y, the readings of the voltmeters are V_1, V_2 and V_3 respectively. Then :

Find a potentail difference varphi_(1) - varphi_(2) between points 1 and 2 of the circuit shown in Fig if R_(1) 1= 10 Omega, R_(2) = 20 Omega, E_(1) = 5.0 V , and E_(2) = 2.0 V . The internal resisances of the current sources are negligible.