Home
Class 10
PHYSICS
A photon of energy 2.16eV is incident on...

A photon of energy 2.16eV is incident on the surface of a metal of photoelectric work function 1.25eV. If the maximum velocity of a photoelectron emitted is `0.566 xx 10^(6) ms^(-1)`, calculate the mass of the electron.

Text Solution

AI Generated Solution

Promotional Banner

Topper's Solved these Questions

  • NATURE OF LIGHT AND PHOTOELECTRIC EFFECT

    CENGAGE PHYSICS|Exercise Challenging Exercise|3 Videos
  • NATURE OF LIGHT AND PHOTOELECTRIC EFFECT

    CENGAGE PHYSICS|Exercise Olympiad and NTSE Level Exercises|9 Videos
  • NATURE OF LIGHT AND PHOTOELECTRIC EFFECT

    CENGAGE PHYSICS|Exercise Mandatory Exercise (Exercise Set III)|16 Videos
  • MAGNETISM

    CENGAGE PHYSICS|Exercise OLYMPIAD AND NTSE LEVEL EXERCISES|8 Videos
  • OPTICAL INSTRUMENTS

    CENGAGE PHYSICS|Exercise OLYMPLAD AND NTSE LEVEL EXERCISES|10 Videos

Similar Questions

Explore conceptually related problems

Monochromatic photons of energy 3.3 eV are incident on a photo sensitive surface of work function 2.4 eV. , maximum velocity of photoelectron is

A photon of energy 8 eV is incident on a metal surface of threshold frequency 1.6 xx 10^(15) Hz , then the maximum kinetic energy of photoelectrons emitted is ( h = 6.6 xx 10^(-34) Js)

Light of wavelength 3000Å is incident on a metal surface whose work function is 1 eV. The maximum velocity of emitted photoelectron will be

Light of frequency 8 xx 10^(15) Hz is incident on a substance of photoelectric work function 6.125 eV . The maximum kinetic energy of the emitted photoelectrons is

Ultraviolet beam of wavelength 280 nm is incident on lithium surface of work function 2.5 eV. The maximum velocity of electron emitted from metal surface is

A photon of energy 7 eV is incident on a metal surface having the work function of 3.75 eV. What is the stopping potential ?

Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV . The minimum kinetic energy of the emitted photo - electrons will be

A photon energy 3.4 eV is incident on a metal having work function 2 eV . The maximum K.E. of photoelectrons is equal to

A photon of energy 8 eV is incident on metal surface of threshold frequency 1.6 xx 10^(15) Hz , The maximum kinetic energy of the photoelectrons emitted ( in eV ) (Take h = 6 xx 10^(-34) Js ).

Photons of energy 1.5 eV and 2.5 eV are incident on a metal surface of work function 0.5 eV. What is the ratio of the maximum kinetic energy of the photoelectrons ?