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Find the total number of proper factors ...

Find the total number of proper factors of the number 35700.

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`because35700=2^(2)xx3^(1)xx5^(2)xx7^(1)xx17^(1)`
`therefore`Required number of odd proper divisors
=Total number of selections of zero 2 and any number of 3's or 5's or 7's or 17's
`=(1+1)(2+1)(1+1)(1+1)-1=23`
`therefore` The sum of odd proper divisors
`=(3^(0)+3^(1))(5^(0)+5^(1)+5^(2))(7^(0)+7^(1))(17^(0)+7^(1))-1`
`=4xx31xx8xx18-1`
`=17856-1=17855`
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ARIHANT MATHS-PERMUTATIONS AND COMBINATIONS -Exercise (Questions Asked In Previous 13 Years Exam)
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