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If \ ^(43)C(r-6)=\ ^(43)C(3r+1)\ then t...

If `\ ^(43)C_(r-6)=\ ^(43)C_(3r+1)\ ` then the value of `r` is

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We have, `((18),(r-2))+2((18),(r-1))+((18),(r))ge((20),(13))`
It means that `.^(18)C_(r-2)+2*.^(18)C_(r-1)+.^(18)C_(r)ge.^(20)C_(13)`
`implies(.^(18)C_(r-2)+.^(18)C_(r-1))+(.^(18)C_(r-1)+.^(18)C_(r))ge.^(20)C_(7)`
`implies.^(19)C_(r-1)+.^(19)C_(r) ge .^(20)C_(7)`
`implies.^(20)C_(r)ge.^(20)C_(7)`
`implies.^(20)C_(r) ge .^(20)C_(13)`
`implies 7 le r le 13`
`therefore r=7,8,9,10,11,12,13`
Hence, the number of values of r are 7.
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ARIHANT MATHS-PERMUTATIONS AND COMBINATIONS -Exercise (Questions Asked In Previous 13 Years Exam)
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