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Total number of divisors of N=2^(5)*3^(4...

Total number of divisors of `N=2^(5)*3^(4)*5^(10)*7^(6)` that are of the form `4n+2,n ge 1`, is equal to

A

54

B

55

C

384

D

385

Text Solution

Verified by Experts

The correct Answer is:
C
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