Home
Class 12
MATHS
Let p=2520, x=number of divisors of p wh...

Let p=2520, x=number of divisors of p which are multiple of 6, y=number of divisors of p which are multiple of 9, then

A

x=12

B

x=24

C

y=12

D

y=16

Text Solution

Verified by Experts

The correct Answer is:
B, D
`becausep=2520=2^(3)*3^(2)*5^(1)*7^(1)`
`=6*2^(2)*3^(1)*5^(1)*7^(1)=9*2^(3)*5^(1)*7^(1)`
`thereforex=(2+1)(1+1)(1+1)(1+1)=24`
and `y=(3+1)(1+1)(1+1)=16`.
Promotional Banner

Topper's Solved these Questions

  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS|Exercise Exercise (Passage Based Questions)|15 Videos

  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|10 Videos

  • PERMUTATIONS AND COMBINATIONS

    ARIHANT MATHS|Exercise Exercise (Single Option Correct Type Questions)|30 Videos

  • PARABOLA

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos

  • PROBABILITY

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|55 Videos

Similar Questions

Explore conceptually related problems

If N = 10800, find the(i) the number of divisors of the form 4m +2,(ii) the number of divisors which are multiple of 10(iii) the number of divisors which are multiple of 15.

The set {x:x is a prime number and divisor of 6} is equal to:

The setA={x:x is a prime number and divisor of 6} is equal to:

Which multiple of 9 is closet to 100000.

Which multiple of 9 is closet to 10,000.

Find the number of divisors of the number N=2^3 .3^5 .5^7 .7^9 which are perfect squares.

The number of proper divisors of 1800, which are also divisible by 10, are: a. 18 b. 27 c. 34 d. 43

Which multiple of 9 is closet to 10,00,000.

Write the following statement in the form ‘if p, then q’ : A number is even if it is a multiple of 2.

The number of proper divisors of 2^(p)*6^(q)*21^(r),AA p,q,r in N , is