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Check the relation rho for reflexive, sy...

Check the relation `rho` for reflexive, symmetry and transitivity:
`alpha rho beta` iff `alpha` is perpendicular to `beta`, where `alpha` and `beta` are straight lines in a plane.

Text Solution

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The relation R is reflexive, since a is divisible by a, R is not symmetric because b is divisible by a but a is not divisible by b. i.e., aRb `cancelimplies` bRa
Again, R is transitive, since b is divisible by a and c is divisible by b, then always c is divisible by a.
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