Home
Class 12
MATHS
Find the value of parameter alpha for...

Find the value of parameter `alpha` for which the function `f(x)=1+alpha\ x` , `alpha!=0` is the inverse of itself.

A

`-2`

B

`-1`

C

1

D

2

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • SETS, RELATIONS AND FUNCTIONS

    ARIHANT MATHS|Exercise Exercise (Single Option Correct Type Questions)|39 Videos

  • SETS, RELATIONS AND FUNCTIONS

    ARIHANT MATHS|Exercise Exercise (More Than One Correct Option Type Questions)|3 Videos

  • SETS, RELATIONS AND FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 2|10 Videos

  • SEQUENCES AND SERIES

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|38 Videos

  • THE STRAIGHT LINES

    ARIHANT MATHS|Exercise The Straight Lines Exercise 8 : (Questions Asked in Previous 13 years Exams)|1 Videos

Similar Questions

Explore conceptually related problems

Find all the values of alpha for which : sin^4 x + cos^4 x + sin 2x +alpha =0 is valid.

Verify the Lagrange's Mean Value Theorem for the functions: f(x) = alpha on [a,b]

Find the value of beta , if the value of alpha is 0.95.

A function f : R rarr R, where R is the set of real numbers, is defined by : f(x)= (alpha x^2+6x-8)/(alpha+6x-8x^2) . Find the interval of values of alpha for which f is onto. Is the function one-one for alpha = 3 ? Justify your answer.

The values of alpha for which the equation alpha^2/(1-tan^2x)=(sin^2+alpha^2-2)/(cos2x) has solution can be

The value of |alpha| for which the system of equation alphax+y+z=alpha-1 x+alphay+z=alpha-1 x+y+alphaz=alpha-1 has no solutions, is ________.

Let the smallest positive value of x for which the function f(x)=sin""(x)/(3)+sin""(x)/(11), ( x in R ) achieves its maximum value be x_(0) . Express x_(0) in degree i.e. x_(0)=alpha^(0) . Then , the sum of the digits in alpha is

If f(x) = alpha x^n , prove that alpha= (f'(1))/n .

Find the interval of alpha for which (alpha, alpha^2, alpha) and (3, 2, 1) lies on same side of x+y-4z+2=0 .