If the vectors AB=3hati+4hatk and AC=5ha...

If the vectors `AB=3hati+4hatk and AC=5hati-2hatj+4hatk` are the sides of a `DeltaABC`, then the length of the median through A is

A

`sqrt(18)`

B

`sqrt(72)`

C

`sqrt(33)`

D

`sqrt(288)`

Text Solution

Verified by Experts

The correct Answer is:

C

PV of `AD=((3+5)hati+(0-2)hatj+(4+4)hatk)/(2)`
`=4hati-hatj+4hatk`
`|AD|=sqrt(16+16+1)=sqrt(33)`

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