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If the resultant of three forces F(1)=ph...

If the resultant of three forces `F_(1)=phati+3hatj-hatk,F_(2)=6hati-hatk and F_(3)=-5hati+hatj+2hatk` acting on a particle has a magnitude equal to 5 units, then the value of p is

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The correct Answer is:
`(2,-4)`
let R be the resultant. Then
`R=F_(1)+F_(2)+F_(3)=(p+1)hati+4hatj`
Given `|R|=5,` therefore `R^(2)=25`
`because(p+1)^(2)+16=25` or p+1=`+-3` or p=2,-4
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