The ratio of the sums of m and n terms of an A.P. is `m^2: n^2`. Show that the ratio of `m^(th)` and `n^(th)` term is (2m - 1 ) : (2n -1).

Options

A. `(2m+1):(2n-1),`
B. `m:n`
C. `(2m-1):(2n-1)`
D. None of these

Explanation

(c) Here, `" "(S_(m))/S_(n)=(m^2)/(n^2) " "[therefore A=1,B=0]` S
` therefore " " (t_(m))/(t_(n))=((2m-1))/((2n-1))`
`implies t_(m):t_(n)= (2m-1):(2n-1)`