If first term of a GP is a, third term is b and `(n+1)th` term is c. The `(2n+1)th` term of a GP is

Options

A. `csqrt((b)/(a))`
B. `(bc)/(a)`
C. `abc`
D. `(c^(2))/(a)`

Explanation

Let common ratio =r
` therefore b=ar^(2) implies r=sqrt((b)/(a))`
Also, `c=ar^(n) implies r^(n)=(c)/(a)`
`therefore t_(2n+1)= ar^(2n)=a(r^(n))^(2)=a((c)/(a))^(2)=(c^(2))/(a)`
Hence, (d) is the correct answer.