Find the value of `0.32bar58`

Explanation

Let `R=0.3258`
`implies R= 0.32585858585"....." " " "......(i)"`
Here, number of figures which are not recurring is 2 and number of figures which are recurring is also 2.
Then, `100R= 32.585858585"....." " " "......(ii)"`
and `10000R= 3258.585858585"....." " " "......(iii)"`
On subtracting Eq.(ii) from Eq.(iii), we get
`9900R= 3226`
`therefore " " R= (3226)/(9900)`
Hence, `" " R= (1613)/(4950)`