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The value of (0.16)^log2.5{1/3+1/3^2+......

The value of `(0.16)^log2.5{1/3+1/3^2+...}` is

A

A. `(1)/(1+a)`

B

B. `(2)/(1+a)`

C

C. `oo`

D

D. None of these

Text Solution

Verified by Experts

The correct Answer is:
B
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