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For three events `A ,B` and `C ,P` (Exactly one of `A` or `B` occurs) `=P` (Exactly one of `B` or `C` occurs) `=P` (Exactly one of `C` or `A` occurs) `=1/4` and `P` (All the three events occur simultaneously) `=1/6dot` Then the probability that at least one of the events occurs, is : `7/(64)` (2) `3/(16)` (3) `7/(32)` (4) `7/(16)`

A

`(3)/(16)`

B

`(7)/(32)`

C

`(7)/(16)`

D

`(7)/(64)`

Text Solution

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The correct Answer is:
C
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