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sin(3theta+alpha)+sin(3theta-alpha)+sin(...

`sin(3theta+alpha)+sin(3theta-alpha)+sin(alpha-theta)-sin(alpha+theta)=cosalpha`

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The correct Answer is:
`{x|x = npi + (-1)^(n)(pi)/(6)}cup {theta|theta = n pi +(-1)^(n) (pi)/(10)} cup {theta|theta = n pi - (-1)^(n)(3pi)/(10)}`
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