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In DeltaABC, prove that "cosec"(A)/(2)+"...

In `DeltaABC`, prove that `"cosec"(A)/(2)+"cosec"(B)/(2)+"cosec"(C)/(2) ge 6` .

Text Solution

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The correct Answer is:
`rArr cosec.(A)/(2)+cosec.(B)/(2)+cosec.(C)/(2) ge 6`
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