Find the value of `1+i^(2)+i^(4)+i^(6)+...+i^(2n),`
where`i=sqrt(-1)` and n in N.

The value of sum sum_(n=1)^(13)(i^n+i^(n+1)) ,where i=sqrt(-1) equals

The value of sum_(n=0)^(100)i^(n!) equals (where i=sqrt(-1))

Find the values of x and y if : (x+iy)(1+i)=1-i where i=sqrt(-1)

Simplify : (1+i^2) +i^4+i^6 .

The value of (1+i)(1+i)^2(1+i)^3(1+i^4) is:

If (1+i)^(2n)+(1-i)^(2n)=-2^(n+1)(where,i=sqrt(-1) for all those n, which are

Find he value of sum_(r=1)^(4n+7)\ i^r where, i=sqrt(- 1).

If z=(i) ^((i) ^(i)) where i= sqrt (−1) ​ , then z is equal to

Find the least positive integral value of n, for which ((1-i)/(1+i))^n , where i=sqrt(-1), is purely imaginary with positive imaginary part.