If z is any complex number satisfying `abs(z-3-2i) le 2`, where `i=sqrt(-1)`, then the maximum value of `abs(2z-6+5i)`, is

If |z-2i|lesqrt(2), where i=sqrt(-1), then the maximum value of |3-i(z-1)|, is

If abs(z+4) le 3 , the maximum value of abs(z+1) is

If z is any complex number, prove that : |z|^2= |z^2| .

If z=(3+4i)^(6)+(3-4i)^(6),"where" i=sqrt(-1), then Find the value of Im(z) .

The equation z^(2)-i|z-1|^(2)=0, where i=sqrt(-1), has.

Express in a complex number if z= (2-i)(5+i)

If z=(i) ^((i) ^(i)) where i= sqrt (−1) ​ , then z is equal to

For every real number c ge 0, find all complex numbers z which satisfy the equation abs(z)^(2)-2iz+2c(1+i)=0 , where i=sqrt(-1) and passing through (-1,4).

If z=ilog_(e)(2-sqrt(3)),"where"i=sqrt(-1) then the cos z is equal to

If z= sqrt3+i , then the argument of z^2 e^(z-i) is equal to :