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The centre of a square ABCD is at z=0, A...

The centre of a square ABCD is at z=0, A is `z_(1)`. Then, the centroid of `/_\ABC` is (where, `i=sqrt(-1)`)

A

(a)`z_(1)(cos pi +- isinpi)`

B

(b)`z_(1)/3(cos pi +- isinpi)`

C

(c)`z_(1)(cos (pi/(2)) +- isin(pi/2))`

D

(d)`z_(1)/3(cos (pi/(2)) +- isin(pi/2))`

Text Solution

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The correct Answer is:
D
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