Home
Class 12
MATHS
The three sides of a triangle are given ...

The three sides of a triangle are given by `(x^2 - y^2)(2x+3y-6) = 0`. If the points (-2,a) lies inside and (b,1) lies outside the triangle, then

A. `2ltalt(10)/(3)`
B. `-2ltalt(10)/(3)`
C. `-1ltblt(9)/(2)`
D. `-1ltblt1`

A

`2ltalt(10)/(3)`

B

`-2ltalt(10)/(3)`

C

`-1ltblt(9)/(2)`

D

`-1ltblt1`

Text Solution

Verified by Experts

The correct Answer is:
A, D
Promotional Banner

Topper's Solved these Questions

  • PAIR OF STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise (Passage Based Questions)|9 Videos

  • PAIR OF STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|5 Videos

  • PAIR OF STRAIGHT LINES

    ARIHANT MATHS|Exercise Exercise (Single Option Correct Type Questions)|12 Videos

  • MONOTONICITY MAXIMA AND MINIMA

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|31 Videos

  • PARABOLA

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|35 Videos

Similar Questions

Explore conceptually related problems

The combined equation of three sides of a triangle is (x^2-y^2)(2x+3y-6)=0 . If (-2,a) is an interior point and (b ,1) is an exterior point of the triangle, then

The sides of a triangle are given by : x-2y+9=0, 3x + y-22 =0 and x + 5y+2=0. Find the vertices of the triangle.

Show that the point (2,3) lies outside the parabola y^2=3x .

If the equations of three sides of a triangle are x+y=1, 3x + 5y = 2 and x - y = 0 then the orthocentre of the triangle lies on the line/lines

If the point (1, 4) lies inside the circle x^(2)+y^(2)-6x-10y+p=0 then p is:

The three sides AB, BC, CA of a triangle are 5x - 3y +2 = 0,x-3y-2=0 and x+y-6=0 respectively. Find equation of the altitude through the vertex A.

The equation of the sides of a triangle are x+2y+1=0, 2x+y+2=0 and px+qy+1=0 and area of triangle is Delta .

The point P(alpha,alpha +1) will lie inside the triangle whose vertices are A(0,3), B(-2,0) and C(6,1) if

The equations of two sides of a triangle are 3x-2y+6=0\ a n d\ 4x+5y-20\ a n d\ the orthocentre is (1,1). Find the equation of the third side.

If the points A(x_1,y_1), B(x_2,y_2) and C(x_3,y_3) are collinear, then area of triangle ABC is: