Home
Class 12
MATHS
Let f(1) (x) and f(2) (x) be twice diffe...

Let `f_(1) (x) and f_(2) (x)` be twice differentiable functions where `F(x)= f_(1) (x) + f_(2) (x) and G(x) = f_(1)(x) - f_(2)(x), AA x in R, f_(1) (0) = 2 and f_(2)(0)=1. "If" f'_(1)(x) = f_(2) (x) and f'_(2) (x) = f_(1) (x) , AA x in R` then the number of solutions of the equation `(F(x))^(2) =(9x^(4))/(G(x))`is...... .

Text Solution

Verified by Experts

The correct Answer is:
2
Promotional Banner

Topper's Solved these Questions

  • CONTINUITY AND DIFFERENTIABILITY

    ARIHANT MATHS|Exercise EXERCISE 6|2 Videos

  • CONTINUITY AND DIFFERENTIABILITY

    ARIHANT MATHS|Exercise Exercise (Subjective Type Questions)|6 Videos

  • CONTINUITY AND DIFFERENTIABILITY

    ARIHANT MATHS|Exercise EXERCISE 5|3 Videos

  • COMPLEX NUMBERS

    ARIHANT MATHS|Exercise Complex Number Exercise 8|3 Videos

  • COORDINATE SYSTEM AND COORDINATES

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|7 Videos

Similar Questions

Explore conceptually related problems

Let f(x) = x^2 and g(x) = 2x + 1 be two real functions. Find : (f + g) (x), (f-g)(x), (fg) (x) and (f/g) (x).

Let f(x) be a fourth differentiable function such f(2x^2-1)=2xf(x)AA x in R, then f^(iv)(0) is equal

Let f: (-1,1) rarr R be a differentiable function with f(0) = -1 and f'(0) = 1 let g(x) =[f(2f(x)+2)]^2 , then g'(0) =

Let f(x)=x^(2)-2xandg(x)=f(f(x)-1)+f(5-f(x)), then

If f:[1,oo)rarrR:f(x) is monotonic and differentiable function and f(1)=1, then number of solutions of the equation f(f(x))=(1)/(x^(2)-2x+2) is/are……

If f_(1) ,(x) and f_(2)(x) are defined on a domain D_(1) , and D_(2) , respectively, then domain of f_(1)(x) + f_(2) (x) is :

If f(x+y) = f(x) + f(y) + |x|y+xy^(2),AA x, y in R and f'(0) = 0 , then

Let g(x) = ln f(x) where f(x) is a twice differentiable positive function on (0, oo) such that f(x+1) = x f(x) . Then for N = 1,2,3 g''(N+1/2)- g''(1/2) =

A function y=f(x) satisfies (x+1)f^(')(x)-2(x^(2)+x)f(x) = e^(x^(2))/(x+1), Aax gt -1 . If f(0)=5 , then f(x) is

Let y=f(x) be a differentiable function such that f(−1)=2,f(2)=−1 and f(5)=3 If the equation f (x)=2f(x) has real root. Then find f(x)