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Let f(x)={x^2|(cos)pi/x|, x!=0 and 0,x=0...

Let `f(x)={x^2|(cos)pi/x|, x!=0 and 0,x=0,x in RR,` then `f` is
a. differentiable both at x = 0 and at x = 2
b. differentiable at x = 0 but not differentiable at x = 2
c. not differentiable at x = 0 but differentiable at x = 2
d. differentiable neither at x = 0 nor at x = 2

A

differentiable both at x = 0 and at x = 2

B

differentiable at x = 0 but not differentiable at x = 2

C

not differentiable at x = 0 but differentiable at x = 2

D

differentiable neither at x = 0 nor at x = 2

Text Solution

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The correct Answer is:
B
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ARIHANT MATHS-CONTINUITY AND DIFFERENTIABILITY-Exercise (Questions Asked In Previous 13 Years Exam)
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