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x=acos^(3)theta,y=asin^(3)theta then fin...

`x=acos^(3)theta,y=asin^(3)theta` then find `(d^(2)y)/(dx^(2))`

Text Solution

Verified by Experts

The correct Answer is:
`(1)/(3a)sec^(4)thetacosectheta`
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