Home
Class 12
MATHS
Let f(x) be a real valued periodic funct...

Let f(x) be a real valued periodic function with domain R such that
`f(x+p)=1+[2-3f(x)+3(f(x))^(2)-(f(x))^(3)]^(1//3)` hold good for all ` x in R ` and some positive constant p, then the periodic of f(x) is

Text Solution

Verified by Experts

The correct Answer is:
f(x) is periodic with period 2p.
Promotional Banner

Topper's Solved these Questions

  • FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 8|8 Videos
  • FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 9|10 Videos
  • FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 6|5 Videos
  • ESSENTIAL MATHEMATICAL TOOLS

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|3 Videos
  • GRAPHICAL TRANSFORMATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|10 Videos

Similar Questions

Explore conceptually related problems

Let f (x) be a real vaued continuous function such that f (0) =1/2 and f(x+y) = f(x) f (4-y) + f(y) f (4-x ) AA x, y in R, then for some real a: a. f(x) is a periodic function b. f(x) is a constant function c. f(x)=1/2 d. f(x)=(cosx)/2

If f(x) is a polynomial function f:R→R such that f(2x)=f (x) f ′′(x) Then f(x) is

Let f(x)=1-x-x^3 .Find all real values of x satisfying the inequality, 1-f(x)-f^3(x)>f(1-5x)

Let F(x)=1+f(x)+(f(x))^2+(f(x))^3 where f(x) is an increasing differentiable function and F(x)=0 has a positive root, then

Let f(x) be a continuous function such that f(0) = 1 and f(x)-f (x/7) = x/7 AA x in R , then f(42) is

Let f(x) is a real valued function defined by f(x)=x^(2)+x^(2) int_(-1)^(1) tf(t) dt+x^(3) int_(-1)^(1)f(t) dt then which of the following hold (s) good?

Let y=f(x) be a differentiable function such that f(−1)=2,f(2)=−1 and f(5)=3 If the equation f (x)=2f(x) has real root. Then find f(x)

Let f:R rarr R be a continuous function such that f(x)-2f(x/2)+f(x/4)=x^(2) . f(3) is equal to

Let f(x) be polynomial function of degree 2 such that f(x)gt0 for all x in R. If g(x)=f(x)+f'(x)+f''(x) for all x, then