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Let f be an injective map with domain ...

Let `f` be an injective map with domain `{x ,\ y ,\ z}` and range {1, 2, 3} such that exactly one of the following statements is correct and the remaining are false. `f(x)=1,\ \ f(y)!=1,\ f(z)!=2` . The value of `f^(-1)(1)` is
(a) `x` (b) `y` (c) `z` (d) none of these

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The correct Answer is:
`f^(-1)(1)=y`
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