Home
Class 12
MATHS
f(x)=1/abs(x), g(x)=sqrt(x^(-2)) . Ident...

`f(x)=1/abs(x), g(x)=sqrt(x^(-2))` . Identical functions or not?

Text Solution

Verified by Experts

The correct Answer is:
Identical
Promotional Banner

Topper's Solved these Questions

  • FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 10|5 Videos

  • FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 11|2 Videos

  • FUNCTIONS

    ARIHANT MATHS|Exercise Exercise For Session 8|8 Videos

  • ESSENTIAL MATHEMATICAL TOOLS

    ARIHANT MATHS|Exercise Exercise (Single Integer Answer Type Questions)|3 Videos

  • GRAPHICAL TRANSFORMATIONS

    ARIHANT MATHS|Exercise Exercise (Questions Asked In Previous 13 Years Exam)|10 Videos

Similar Questions

Explore conceptually related problems

f(x)=sqrt(1-x^(2)), g(x)=sqrt(1-x)*sqrt(1+x) . Identical functions or not?

f(x)=log_(e)x, g(x)=1/(log_(x)e) . Identical function or not?

f(x)=In" "e^(x), g(x)=e^(Inx) . Identical function or not?

f(x)= 1/([sqrt(|x|-x)]) . Domain of the function is :

Statement I The function f(x) = int_(0)^(x) sqrt(1+t^(2) dt ) is an odd function and STATEMENT 2 : g(x)=f'(x) is an even function , then f(x) is an odd function.

f(x)=secx, g(x)=1/cosx Identical or not?

Let g(x) be a function defined on [-1,1]dot If the area of the equilateral triangle with two of its vertices at (0,0)a n d(x ,g(x)) is (sqrt(3))/4 , then the function g(x) is g(x)=+-sqrt(1-x^2) g(x)=sqrt(1-x^2) g(x)=-sqrt(1-x^2) g(x)=sqrt(1+x^2)

Let f_(1) (x) and f_(2) (x) be twice differentiable functions where F(x)= f_(1) (x) + f_(2) (x) and G(x) = f_(1)(x) - f_(2)(x), AA x in R, f_(1) (0) = 2 and f_(2)(0)=1. "If" f'_(1)(x) = f_(2) (x) and f'_(2) (x) = f_(1) (x) , AA x in R then the number of solutions of the equation (F(x))^(2) =(9x^(4))/(G(x)) is...... .

f(x)=sqrt(x-1)+sqrt(2-x) and g(x)=x^(2)+bx+c are two given functions such that f(x) and g(x ) attain their maximum and minimum values respectively for same value of x , then