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f(x)={{:(x-1",", -1 le xle 0),(x^(2)",",...

`f(x)={{:(x-1",", -1 le xle 0),(x^(2)",",0 lt x le 1):}` and g(x)=sinx. Find `h(x)=f(abs(g(x)))+abs(f(g(x))).`

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The correct Answer is:
h(x)=`{{:(2sinx",", -1 lt x lt 0),(2sin^(2)x",", 0 lt x le 1):}`
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