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Let f(x)={{:(x+1",",x le 1),(2x+1",", 1 ...

Let `f(x)={{:(x+1",",x le 1),(2x+1",", 1 lt x le 2):}`
`"and "g(x)={{:(x^(2)",",-1 le x lt 2),(x+2",", 2 le x le 3):}`
Find (fog).

Text Solution

Verified by Experts

The correct Answer is:
gof=`{(x+1)^(2), -2 le x le 1}`
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