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Let f:(0,1)->R be defined by f(x)=(b-x)...

Let `f:(0,1)->R` be defined by `f(x)=(b-x)/(1-bx)`, where b is constant such that `0 ltb lt 1` .then ,

A

(a)f is not invertible on (0,1)

B

(b)`f ne f^(-1)` on (0,1) and `f'(b)=1/(f'(0))`

C

(c)`f=f^(-1)` on (0,1) and `f'(b)=1/(f'(0))`

D

(d)`f^(-1)` is differentiable on (0,1)

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The correct Answer is:
B
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